02 Apr

Exponential function

Reverted edits by 111.68.108.100 (talk) to last revision by Emijrpbot
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Revision as of 15:40, 2 April 2013
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:: $z=| \exp \left( x + i y \right)|$

:: $z=| \exp \left( x + i y \right)|$

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The modulus of the value is the same razi as the value of the exponential of just the real part of the operand. Since the real part behaves as a cosine across the complex plane, and the imaginary part like a sine, the modulus which is related to the real part squared plus the imaginary part squared. As $\sin^2x + \cos^2x =1$ , it makes sense that the modulus is invariant in the imaginary direction.
+
The modulus of the value is the same as the value of the exponential of just the real part of the operand. Since the real part behaves as a cosine across the complex plane, and the imaginary part like a sine, the modulus which is related to the real part squared plus the imaginary part squared. As $\sin^2x + \cos^2x =1$ , it makes sense that the modulus is invariant in the imaginary direction.

{| align=center

{| align=center
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:: $z=\arg \left (\exp \left( x + i y \right)\right)$

:: $z=\arg \left (\exp \left( x + i y \right)\right)$

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The argument of the exponential function is simply the argument of the operand. The density plot has a linear colour function (an equal change in colour is representative fahad mian of an equal change in the value of the point). Red is lowest, green is zero and blue is highest.
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The argument of the exponential function is simply the argument of the operand. The density plot has a linear colour function (an equal change in colour is representative of an equal change in the value of the point). Red is lowest, green is zero and blue is highest.

{| align=center

{| align=center

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