24 Mar

Commons:Village pump/Copyright

‎Copyright of derivative work, i.e. picture of a commercial product (United States): r
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Revision as of 22:43, 24 March 2013
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::::Quick and incomplete answer: if the copyrighted content is a focus of the image it is probably infringing. Incidental inclusion of copyrighted content in a photograph of something else, particularly at low resolution or out of focus or including only a small part of the original may be acceptable. In particular, store shelf displays (not including posters etc.) are often ok. See [[Commons:De minimis]] for a more complete explanation. Per your last query, it is certainly a derivative of each included work individually. I'm not sure what you mean by "of all the works" but if you are thinking of a photograph of an assembly of copyrighted works, then if that assembly was copyrightable then it is a derivative of that copyright also. [[User:Dankarl|Dankarl]] ([[User talk:Dankarl|talk]]) 21:50, 24 March 2013 (UTC)

::::Quick and incomplete answer: if the copyrighted content is a focus of the image it is probably infringing. Incidental inclusion of copyrighted content in a photograph of something else, particularly at low resolution or out of focus or including only a small part of the original may be acceptable. In particular, store shelf displays (not including posters etc.) are often ok. See [[Commons:De minimis]] for a more complete explanation. Per your last query, it is certainly a derivative of each included work individually. I'm not sure what you mean by "of all the works" but if you are thinking of a photograph of an assembly of copyrighted works, then if that assembly was copyrightable then it is a derivative of that copyright also. [[User:Dankarl|Dankarl]] ([[User talk:Dankarl|talk]]) 21:50, 24 March 2013 (UTC)

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::::You'll find a very good explanation at [[Commons:Image_casebook#Product_packaging]]. Cheers -- [[User:Orionist|'''Orionist''']] ★ [[User talk:Orionist|talk]] 22:43, 24 March 2013 (UTC)

== {{User|Edseeman}} ==

== {{User|Edseeman}} ==

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